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x^2+45x=2.079
We move all terms to the left:
x^2+45x-(2.079)=0
We add all the numbers together, and all the variables
x^2+45x-2.079=0
a = 1; b = 45; c = -2.079;
Δ = b2-4ac
Δ = 452-4·1·(-2.079)
Δ = 2033.316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2033.316}}{2*1}=\frac{-45-\sqrt{2033.316}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2033.316}}{2*1}=\frac{-45+\sqrt{2033.316}}{2} $
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